fix: Add propertyName to caseJson for iframe form data
Problem: - Form was empty because propertyName was not passed to iframe - JavaScript code checked for injected.propertyName but it was undefined - Only case (normalized) was passed, not the original propertyName Solution: - Added propertyName to caseJson object that gets embedded in HTML - Now JavaScript code can access both case and propertyName - This allows the form to properly display data from send_to_form_approve.draft Files: - frontend/src/components/form/generateConfirmationFormHTML.ts: Added propertyName to caseJson
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62
docs/CHECK_DUPLICATES.sql
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62
docs/CHECK_DUPLICATES.sql
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-- SQL запрос для проверки дубликатов claim_id в таблице clpr_claims
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-- Показывает записи с одинаковым claim_id в payload, но разными ID
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-- 1. Найти все claim_id, которые встречаются более одного раза
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WITH claim_id_counts AS (
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SELECT
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payload->>'claim_id' AS claim_id,
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COUNT(*) AS count,
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array_agg(id ORDER BY updated_at DESC) AS ids,
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array_agg(updated_at ORDER BY updated_at DESC) AS updated_dates
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FROM clpr_claims
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WHERE payload->>'claim_id' IS NOT NULL
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GROUP BY payload->>'claim_id'
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HAVING COUNT(*) > 1
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)
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SELECT
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claim_id,
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count AS duplicate_count,
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ids AS record_ids,
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updated_dates,
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-- Показываем разницу во времени между записями
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updated_dates[1] - updated_dates[array_length(updated_dates, 1)] AS time_diff
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FROM claim_id_counts
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ORDER BY count DESC, claim_id
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LIMIT 20;
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-- 2. Детальная информация о дубликатах (для конкретного claim_id)
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-- Замените 'YOUR_CLAIM_ID' на реальный claim_id
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/*
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SELECT
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id,
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payload->>'claim_id' AS claim_id,
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status_code,
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channel,
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created_at,
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updated_at,
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-- Показываем, есть ли send_to_form_approve в разных записях
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CASE
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WHEN payload->'send_to_form_approve' IS NOT NULL THEN 'YES'
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ELSE 'NO'
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END AS has_send_to_form_approve,
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-- Показываем размер payload для сравнения
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pg_column_size(payload) AS payload_size_bytes
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FROM clpr_claims
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WHERE payload->>'claim_id' = 'YOUR_CLAIM_ID'
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ORDER BY updated_at DESC;
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*/
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-- 3. Статистика: сколько всего дубликатов
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SELECT
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COUNT(*) AS total_duplicate_claim_ids,
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SUM(count) AS total_duplicate_records
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FROM (
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SELECT
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payload->>'claim_id' AS claim_id,
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COUNT(*) AS count
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FROM clpr_claims
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WHERE payload->>'claim_id' IS NOT NULL
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GROUP BY payload->>'claim_id'
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HAVING COUNT(*) > 1
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) AS duplicates;
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